Two capacitors in series to store energy

For two equally sized capacitors, the charge and voltage are the same and the voltage across each is one half the battery voltage. Therefore the total stored energy is $$E_ {series}=frac {1} {2}C (V/2)^2+frac {1} {2}C (V/2)^2=frac {CV^2} {4}$$

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Capacitor

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[FREE] Two capacitors, C_1 = 18.0, mu F and C_2 = 36.0, mu F

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(c) What potential difference would be required across the same two capacitors connected in series for the combination to store the same amount of energy as Two capacitors, C1 = 29.0 µF and C2 = 7.00

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About Two capacitors in series to store energy

About Two capacitors in series to store energy

For two equally sized capacitors, the charge and voltage are the same and the voltage across each is one half the battery voltage. Therefore the total stored energy is $$E_ {series}=frac {1} {2}C (V/2)^2+frac {1} {2}C (V/2)^2=frac {CV^2} {4}$$

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